10[z-(10z+2)+2]=4(z+2)

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Solution for 10[z-(10z+2)+2]=4(z+2) equation:


Simplifying
10[z + -1(10z + 2) + 2] = 4(z + 2)

Reorder the terms:
10[z + -1(2 + 10z) + 2] = 4(z + 2)
10[z + (2 * -1 + 10z * -1) + 2] = 4(z + 2)
10[z + (-2 + -10z) + 2] = 4(z + 2)

Reorder the terms:
10[-2 + 2 + z + -10z] = 4(z + 2)

Combine like terms: -2 + 2 = 0
10[0 + z + -10z] = 4(z + 2)
10[z + -10z] = 4(z + 2)

Combine like terms: z + -10z = -9z
10[-9z] = 4(z + 2)

Remove brackets around [-9z]
10 * -9z = 4(z + 2)

Multiply 10 * -9
-90z = 4(z + 2)

Reorder the terms:
-90z = 4(2 + z)
-90z = (2 * 4 + z * 4)
-90z = (8 + 4z)

Solving
-90z = 8 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-90z + -4z = 8 + 4z + -4z

Combine like terms: -90z + -4z = -94z
-94z = 8 + 4z + -4z

Combine like terms: 4z + -4z = 0
-94z = 8 + 0
-94z = 8

Divide each side by '-94'.
z = -0.08510638298

Simplifying
z = -0.08510638298

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